Math, asked by pzalavadiya64, 2 months ago

d/dx (log(X)-cot(X))​

Answers

Answered by tuhingenius2006
0

Answer:

Step-by-step explanation:

Differentiate using the chain rule, which states that  

d

d

x

[

f

(

g

(

x

)

)

]

is  

f

'

(

g

(

x

)

)

g

'

(

x

)

where  

f

(

x

)

=

ln

(

x

)

and  

g

(

x

)

=

cot

(

x

)

.

Tap for more steps...

1

cot

(

x

)

d

d

x

[

cot

(

x

)

]

Rewrite  

cot

(

x

)

in terms of sines and cosines.

1

cos

(

x

)

sin

(

x

)

d

d

x

[

cot

(

x

)

]

Multiply by the reciprocal of the fraction to divide by  

cos

(

x

)

sin

(

x

)

.

sin

(

x

)

cos

(

x

)

d

d

x

[

cot

(

x

)

]

Convert from  

sin

(

x

)

cos

(

x

)

to  

tan

(

x

)

.

tan

(

x

)

d

d

x

[

cot

(

x

)

]

The derivative of  

cot

(

x

)

with respect to  

x

is  

csc

2

(

x

)

.

tan

(

x

)

(

csc

2

(

x

)

)

Simplify the expression.

Tap for more steps...

csc

2

(

x

)

tan

(

x

)

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