Question

d/dx ( logx cosec x ) = ​

Answer 1

Answer:

Step-by-step explanation:

d/dx ( logx cosec x )

=logx d/dx cosecx + cosecx d/dx logx

d/dx of logx =1/x

d/dx of cosecx =−cot x cosec x.

so

=log x(−cot x cosec x.)+cosecx(1/x) ans