d/dx(logx+x-2)*5 please answer completely
Answers
Answered by
1
Answer:
=e
logx
5
=x
5
dx
dy
=5x
5−1
=5x
4
.
solution
Answered by
1
f(x)=[logx+x-2]⁵
Differentiate using the chain rule which is:
d/dx [f(g(x))]=[f'(g(x))].[g'(x)]
f'(x)=5[logx+x-2]⁴. [(1/x)+1]
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