Question

d/dx of [(4x+2)×(5x^2+4)]​

Answer 1

Answer:

60x² + 20x + 16

Step-by-step explanation:

(f × g)' = f' × g + f × g'

$\frac{d(4x+2)}{dx} (5x^2 + 4)+\frac{d(5x^2+4)}{dx}$(4x + 2)  

$\frac{d(4x+2)}{dx}=4$

$\frac{d(5x^2+4)}{dx} =10x$

4(5x² + 4) + 10x(4x + 2) = 20x² + 16 + 40x² + 20x =

60x² + 20x + 16