Question

d/dx of log |sec x + tanx |

Answer 1

d/dx [log(sec x + tan x)]
= 1/secx+tanx . d/dx(secx+tanx)
= sec x .tan x + sec^2 x / secx + tanx
= sec x ( tanx + secx)/ tanx + secx
= Sec x

Answer 2

$<b>●•••••••☆Hello User☆•••••••● 《《Here is your answer》》 <hr size = 3 width = 300 color = #000000 ><font color = green> ‍‌‌‌ = d / dx log( |sec x + tan x | ) = d log( |sec x + tan x | ) / d | sec x + tan x | × d |sec x + tan x | / dx = 1 / | sec x + tan x | × (sec x.tan x + sec²x) = sec x (sec x + tan x) / | sec x + tan x | = sec x </font> <hr size = 3 width = 300 color = #000000 > ●•••••••☆Brainly Star☆•••••••●</b> <b>॥ॐ 卐 ☪ ✝ ॥</b>$