Math, asked by harshalzade3031, 10 months ago

d/dx of [tan(2x)]^3

Answers

Answered by banuthenu30

0

Answer:

6tan 2x sec power 2 2x

Step-by-step explanation:

d/dx(tan2x)

3(tan2x)

sec^2x×2

=6tan 2x sec power2 2x

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