d/dx of (x^2-3)/(x^3+1)
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Answered by
3
Answer:
(-x⁴+9x²+2x)/(x³+1)²
Step-by-step explanation:
u=x²-3
v=x³+1
du/dx = 2x
dv/dx = 3x²
dy/dx = (v du/dx - u dv/dx)/v²
=[(x³+1)2x - (x²-3)3x²]/(x³+1)²
=(2x⁴+2x-3x⁴+9x²)/(x³+1)²
=(-x⁴+9x²+2x)/(x³+1)²
babushall:
thanks for helping me
Answered by
1
HYY DEAR
THIS IS YOUR ANSWER
Answer:
(-x⁴+9x²+2x)/(x³+1)²
Step-by-step explanation:
u=x²-3
v=x³+1
du/dx = 2x
dv/dx = 3x²
dy/dx = (v du/dx - u dv/dx)/v²
=[(x³+1)2x - (x²-3)3x²]/(x³+1)²
=(2x⁴+2x-3x⁴+9x²)/(x³+1)²
=(-x⁴+9x²+2x)/(x³+1)²
THANKS MY ANSWERE
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