Math, asked by babushall, 1 year ago

d/dx of (x^2-3)/(x^3+1)​

Answers

Answered by s280012
3

Answer:

(-x⁴+9x²+2x)/(x³+1)²

Step-by-step explanation:

u=x²-3

v=x³+1

du/dx = 2x

dv/dx = 3x²

dy/dx = (v du/dx - u dv/dx)/v²

=[(x³+1)2x - (x²-3)3x²]/(x³+1)²

=(2x⁴+2x-3x⁴+9x²)/(x³+1)²

=(-x⁴+9x²+2x)/(x³+1)²


babushall: thanks for helping me
s280012: wlcm
Answered by kavitasingh143
1

HYY DEAR

THIS IS YOUR ANSWER

Answer:

(-x⁴+9x²+2x)/(x³+1)²

Step-by-step explanation:

u=x²-3

v=x³+1

du/dx = 2x

dv/dx = 3x²

dy/dx = (v du/dx - u dv/dx)/v²

=[(x³+1)2x - (x²-3)3x²]/(x³+1)²

=(2x⁴+2x-3x⁴+9x²)/(x³+1)²

=(-x⁴+9x²+2x)/(x³+1)²

THANKS MY ANSWERE

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