Question

d/dx root(1+x^2)-log[1/x+root(1+x^2)/root(x^2)​

Answer 1

Step-by-step explanation:

d/dx[√ (1+x²)-log(1/x+√(1+x²) /√x²)]

=> d/dx√(1+x²) - d/dx log[ 1/x+√(1+x²)] - d/dx logx

=> -2x/2√(1+x²) - 1/ [ 1/x+√( 1+x²)]

× [( -1/x²)-2x/2√(1+x²)] - 1/x

=> -x/√(1+x²) -x/ [1+x√(1+x²)][ -1/x²- x/√(1+x²)] -1/x

Hope this helps you