Question

d/dx [sin^-1 (2x/ 1+x^2) ]​

Answer 1

Answer:

ex 5.3, 9 Find dy/dx in, y = sin^(−1) (2x/( 1 + 2x2 )) y = sin^(−1) (2x/( 1 + 2x2 )) Putting x = tan θ y = sin^(−1) (2x/( 1 + x2 )) y = sin^(−1) ((2

Step-by-step explanation:

Answer 2

Your answer is 0

LHS cancled by RHS

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