Question

d/dx sin^2 [ln(sec(x))]







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Answer 1

Answer:

2 sin [ ln (sec x) ] cos [ ln (sec x) ] tan x = sin 2[ln (sec x)] . tan x

Step-by-step explanation:

Applying chain rule,

d/dx sin^2 [ln (sec x) ] = 2 sin [ln (sec x) ] . d/dx sin [ln (sec x)]

                                   = 2 sin [ln (sec x) ] . cos [ln (sec x)] . 1/sec x . sec x . tan x

                                  = 2 sin [ln (sec x)]. cos [ ln (sec x)]. tan x

                                   = sin 2[ln (sec x)] . tan x         {2 sin x cos x = sin 2x}