Question

d/ dx sin log(1+x²) ​

Answer 1

Answer:

$\frac{2x}{1+x^2} cos(log(1+x^2))$

Step-by-step explanation:

d/dx sin(log(1+x²)) = cos(log(1+x²)) d/dx log(1+x²)  =   cos(log(1+x²))*(1/1+x²) d/dx(1+x²) = $\frac{2x}{1+x^2} cos(log(1+x^2))$