Math, asked by MAVULURIHARSHITHBOSS, 1 year ago

d/dx [sin(x^2+1)]is___________

Answers

Answered by MMXNiloy
0
Derivative of sin((x^2)+1) is 2x × cos((x^2)+1).
Answered by AanyaKandwal
10
ddx(y)=ddx(sin2(x))ddx(y)=ddx(sin2(x))
=2cos(x)sin(x)
=y'=2cos(x)sin(x)
=Replace y'y′ with dydxdydx.

dydx=sin(2x)

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