Question

d/dx sin x^3 find the derivative​

Answer 1

Answer:

use chain rule

Step-by-step explanation:

$f(x)= sin^3x f'(x)=?$

here use first d/dx($x^n$)= $nx^{n-1}$

we get 3sinx²cosx

you might wonder where did cosx come from, it comes from chain rule,incase you don't know chain rule,i'll be happy to teach you chain rule, message mere here if you want to learn