Math, asked by pushpakala086, 11 months ago

d/dx (sin x) , d/dx (cos x), d/dx (tan x), d/dx (sec x), d/dx (cosec x), d/dx (cot x) ....give the answer of these (no spamming)

Answers

Answered by rishabh8670
8

Step-by-step explanation:

 (i)\frac{d}{dx} (sin \: x) = cos \: x \\ (ii) \frac{d}{dx} (cos \: x) =   - sin \: x \\ (iii) \frac{d}{dx} (tan \: x) =  {sec}^{2} x \\ (iv) \frac{d}{dx} (sec \: x) = tan \: x \: sec \: x \\ (v) \frac{d}{dx} (cot \: x) =  { - cosec}^{2} x \\ (vi) \frac{d}{dx} (cosec \: x)  =  - cot \: x \: cosec \: x

Hope you have got it

Answered by robiulawalshuvo70
3

Answer:

d/dx sin x = cosx

d/dx cos x = -sinx

d/dx tan x = Sec2x

d/dx sec x = sec x tan x

d/dx cot x = - cosec2x

d/dx cosec x = -cosec x cot x

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