Question

d/dx (sin x) , d/dx (cos x), d/dx (tan x), d/dx (sec x), d/dx (cosec x), d/dx (cot x) ....give the answer of these (no spamming)

Answer 1

Step-by-step explanation:

$(i)\frac{d}{dx} (sin \: x) = cos \: x \\ (ii) \frac{d}{dx} (cos \: x) = - sin \: x \\ (iii) \frac{d}{dx} (tan \: x) = {sec}^{2} x \\ (iv) \frac{d}{dx} (sec \: x) = tan \: x \: sec \: x \\ (v) \frac{d}{dx} (cot \: x) = { - cosec}^{2} x \\ (vi) \frac{d}{dx} (cosec \: x) = - cot \: x \: cosec \: x$

Hope you have got it

Answer 2

Answer:

d/dx sin x = cosx

d/dx cos x = -sinx

d/dx tan x = Sec2x

d/dx sec x = sec x tan x

d/dx cot x = - cosec2x

d/dx cosec x = -cosec x cot x