Physics, asked by sriharinivs, 5 hours ago

d/dx [√tanx^2] is : (i) x secx^2 / √tanx^2 (ii) sec x / cosx^2 (iii) √cotx^2 / cosx (iv) x^2 / tanx^2 .

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Answered by digpalsing8

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Answer:

Know you be able to come to

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