d/dx (tanx) = sec(x)^2
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d/dx tanx=d/dx sinx/cosx=d/dx (sinx)/cosx +sinx d/dx (1/cosx)
=1+sinx(sinx/cos²x)=1+sin²x/cos²x=1/cos²x=sec²x
Answered by
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Assumption
y = tanx
Also,
y + δy = tan(x + δx)
Hence,
Therefore,
Therefore,
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