Question

d/dx × (x^4 - 2 sin x + 3 cos x)
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Answer 1

Answer:

d/dx (x4 -2sinx + 3cosx)

= d/dx (x4) - d/dx (2sinx) + d/dx (3cosx) ----1

i] d/dx (x4) = 4.x4-1 = 4x3

ii] d/dx (2sinx)= 2. d/dx(sinx)= 2cosx

iii] d/dx (3cosx)= 3. d/dx(cosx)= -3sinx

putting i,ii,iii in 1,

d/dx (x4 -2sinx + 3cosx) = 4x3 -2cosx - 3sinx

Step-by-step explanation:

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