Question

d/dx (x^5+cosx-3x)
please help me out
urgent!!!!​

Answer 1

Step-by-step explanation:

Lim(x→0) {5xcosx. - 3sinx }/(2x² + tan2x }

put x = 0 for checking which form of limit possible here,

x = 0 , then, 0/0 hence,

we can use L- Hospital rule .

Lim(x→0) { 5xcosx - 3(sinx/x)× x }/{ 2x² + (tan2x/2x) × 2x }

use ,

Lim(x→0) sinx/x = 1

Lim (x→0) tanx/x = 1

now,

Lim(x→0) { 5x. cosx - 3x }/{2x² + 2x }

Lim(x→0) { 5cosx - 3}/{2x + 2 }

now ,again put x = 0

we get fintie value

e.g { 5 × 1 - 3 }/{ 0 + 2}

= 2/2 = 1

hence, value of limit = 1

Hopeit helps MRK ME As BRAINLIEST