Question

d/dx(x^x^2) differentiate it please solve it
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Answer 1

Answer:

dy/dx = x^x^2 ( x + 2x ln x).

Step-by-step explanation:

y =  x^x^2

First taking logs is one way to do this:

ln y = x^2 lnx

dy/dx * 1/y = x^2 * 1/x + 2x ln x

dy /dx * 1/y =   x + 2x lnx

dy/dx = (x + 2x lnx) * y

dy/dx = x^x^2 ( x + 2x ln x)