Question

d/dx (x²+2^x+2²)
find dy/dx​

Answer 1

Answer:

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Answer 2

Answer:

$2x+2^{x} log(2)$

Step-by-step explanation:

$x^{2} +2^{x} +2^{2} \\\\x^{2} +2^{x} +4\\\\\frac{dy}{dx} =2x+2^{x}log(2) + 0\\\\\frac{dy}{dx} =2x+2^{x}log(2)$       ← THIS IS THE ANSWER.

[Derivative of $2^{x}$] :

$y = 2^{x} \\\\Taking log both side,\\\\logy=log(2^{x})\\\\logy =xlog(2)\\\\\frac{1}{y} .\frac{dy}{dx} =(1)log2\\\\\frac{dy}{dx} =ylog2\\\\\frac{dy}{dx} =2^{x} log2$