Math, asked by AnekTheMan, 9 months ago

d/dx y[log(sinx)] =?

Answers

Answered by saharounak093
2

Answer:cot x

Step-by-step explanation:y=log(sinx)

By chain rule

First the log function and then within function

dy/dx=d/dx{log(sin x)}

dy/dx=(1/sinx)×d/dx(sin x)

dy/dx=(1/sinx)×cos x

dy/dx=cot x

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