d/dx y[log(sinx)] =?
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Answer:cot x
Step-by-step explanation:y=log(sinx)
By chain rule
First the log function and then within function
dy/dx=d/dx{log(sin x)}
dy/dx=(1/sinx)×d/dx(sin x)
dy/dx=(1/sinx)×cos x
dy/dx=cot x
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