Physics, asked by dashsrirupa, 2 months ago

d/dy(4y³+2y²+3y) derivatives​

Answers

Answered by Anonymous
1

Explanation:

d/dy(4y^3 + 2y^2 + 3y)

=1(4y^3 + 2y^2 + 3y) * (3 * 4 * y^(3 - 1) + 2 * 2 * y^(2 - 1) + 3 * y^(1 - 1))

=1(4y^3 + 2y^2 + 3y) * (12 y^2 + 4 * y^1 + 3 * y^0)

=1(4y^3 + 2y^2 + 3y) * (12 y^2 + 4 * y^1 + 3 * 1)

= 1(4y^3 + 2y^2 + 3y) * (12 y^2 + 4 * y^1 + 3)

= 1(4y^3 + 2y^2 + 3y) * (12 y^2 + 4 * y^1 + 0)

= 48y^5 + 40y^4 + 44y^3 + 12y^2

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