Math, asked by jbharatir, 1 month ago

А
D
E
95°
45°
B
In the figure above, ABC and CDE are
equilateral triangles. Find ZADE in
degrees
options
35
30
40
a
45​

Answers

Answered by barani7953
0

Step-by-step explanation:

Angle DEC = 60

Angle DEA = 120 (180-DEC = supplementary angle)

Also CEF = 60+Y = Angle EBC + Angle ECB

60+Y = 60+EBC

EBC = Y

Hence we can say,

ED is parallel to BC (alternate angles)

Extend ED till it cut AB at H

Such that angle HEA = angle CED = 60° (opposite angle)

Now. AHE is an equilateral triangle too.

AE = ED

In triangle AED

Angle AED + EAD + EDA = 180

120 + 2EAD = 180

2EAD = 60

EAD = 30°

Draw an altitude EG such that it meet AD at G and

Extend EG such that it meet BC at I.

Now HBEI is a parallelogram, whose opposite angles are equal.

Answered by kishorigandhi51
0

Answer:

no figure is attached.

please attach the same

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