D, E and F are midpoint of the side BC, CA and AB respectively of ∆ ABC. then ∆ DEF is congruent to triangle *
∆ABC
∆AEF
∆BFD, ∆CDE
∆AFE, ∆BFD, ∆CDE
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Answer:
Answer IS AFE,BFD,CDE
Step-by-step explanation:
According to mid point then
OE=½ AB DE ANGLE AB
DE=AF -1)
similarly
FD//AC and FO=½ AC=AE-ii)
in angle AFE and angle DFE
AF=DE (byi)
AE = DF
FE= FE ( COMMON)
angle AFE =DEF(sss)
angle DEF=angle CED
angle DEF=angle BFD
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