D,E and F are respectively the mid points of the sides BC,CA and AB of a triangle ABC. Show that area of DEF =1\2ar(ABC)
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ITS Simple.Just a little logic and visualisation and successfully work.
First by the basic proportionality theorem the points are going to be in same ratio.Hence the areas are also eventually going to be in a specific ratio. And this is half........
First by the basic proportionality theorem the points are going to be in same ratio.Hence the areas are also eventually going to be in a specific ratio. And this is half........
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