Question

D E AND F are respectively the mid pts of AB BC AC of ABC.find the ratio of areas of ABC DEF

Answer 1

if d is midpoint of AB then AE=EB and fis mid point of BC
from the problem
ar( def) = ar(afe) =ar(fec)=ar(Ade) as the pllgm diagonal divides it into two congruent parts of equal area
ar(Abc) =ar(def)+ar(afe)+ar(fec)+,ar(Ade)
=4ar(def)
then ar(Abc):ar(def)=4:1