Question

D E and F are respectively the midpoints of the sides BC CA and ab of angle abc show that BDEF is a parallelogram

Answer 1

I hope this will help you

Answer 2

$\textbf{\huge{ANSWER:}}$

Given:
D, E and F are midpoints of BC, CA and AB respectively

To Prove:
BDEF is a ||gm

Proof:
As, F and E are midpoints (Given)

$FE = \frac{1}{2} BC$
And also,

FE || BC

Both are jus because of the Mid-point Theorem.

The Mid-point Theorem states that the line joining the midpoints of two sides of a triangle is equal and is parallel to the third side of the triangle.

Thus, as D is midpoint of BC (Given):
BD = FE

And, FE || BC (Proved)

Thus, BDEF is a ||gm

Hence Proved!

Hope it Helps!! :)