Question

D, E and F are the mid-point of sides BC, CA and AB of a △ABC. If AB = 3 cm, BC = 4 cm and CA = 4 cm, then the perimeter of △DEF is​

Answer 1

Answer:

Given perimeter of △ABC=12.8cm

⇒AB+BC+AC=12.8cm

DE=

2

1

AB,EF=

2

1

BC and DF=

2

1

AC

∴AB=2DE,BC=2EF,AC=2DF

As, D,E,F are the mid points of BC,AB and AC

∴ By mid point theorem, the equations are possible

⇒2DE+2EF+2DF=12.8cm

⇒DE+EF+DF=

2

12.8

=6.4cm

i.e, perimeter of △DEF=DE+EF+DF=6.4cm

solution

Answer By

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Answer 2

Answer:

It's a shape of what triangle, quadrilateral,rectangle,square, trapezium, parallelogram,rhombus or what .....??