D, e, f are midpoint of sides bc, ca, and ab of triangle abc. if perimeter of triangle abc is 12.8 cm, then find perimeter of triangle def?
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I think you will satisfy with this answer.
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DF || BC and 2DF = BC {mid-point theorem}
similarly EF || AB and 2EF = AB and DE || AC and 2DE = AC
DFBC=EFAB=DEAC=12DFBC=EFAB=DEAC=12
=>ABC EFD=>ABC EFD
=>Ar.EFDAr.ABC=(EFAB)2=>Ar.EFDAr.ABC=(EFAB)2
let the area of DEF be x cm2cm2
=>x20=(12)2=>x20=(12)2
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