D,E,F are the mid points of BC, CA and AB of triangle ABC and BE intersect in G, then AG + BG + CG is equal to ?
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Answer:
AGAD=BGBE=CGCF=23 ...(i)
Now AG+BG+CG
= 23AD+23BE+23CF (using equation (i))
= 12(AD+BE+CF)
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