Question

D
Electrovalent compounds are
(a) Good conductor of electricity
(b) Polar in nature
1) Low M.P. and low B.P.
(d) Easily available
​

Answer 1

Answer:

Polar in nature.

Answer 2

Answer to your question =>

ANSWER

MnO4+C2H2O4⇌Mn2 + CO2 + H2OMn + 7

O−2-4+C2+3H2+1O4−2

⇌

Mn20+C+4O2−2 +H2+O−2

Oxidation:

C2+3H21O4−2⟶ C+4O2−2

Rediuction:

Mn+7O4−−2

⟶

Mn20

Balancing on both sides;O:C

2H2O4⟶2CO2

+2H+R:2MnO4− ⟶Mn2

+8H2O⇒O:C2H2O4

⟶2CO2

+2H+

+2e

−

R:14e

−

+2MnO

4

−

+16H

+

⟶Mn

2

+8H

2

O

__________________________________________

7C

2

H

2

O

4

⟶14CO

2

+14H

+

+14e

−

2MnO

4

−

+16H

+

+14e

−

⟶Mn

2

+8H

2

O

⇒7C

2

H2O4

+2MnO4

−

+16H +

+14e-- ⇌14CO2 +MN2

+14H+ +8H2O+14e

−

❤Sweetheart❤

$....$