d) Examine whether the function () = sin(log(x + + D) is an odd or even function,
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1
Answer:
ok
Step-by-step explanation:
Well,as you know that,
sin( -x ) = - sin x =>f(-X)=-f(x) =>odd function
csc ( -x ) = - csc x ;similarly odd function
cos ( -x ) = cos x
; but this is an even function; f(-x)=f(x)
sec (-x ) = sec x
; even function
tan ( -x ) = - tan x
; odd function
tan ( -x ) = - cot x ;and odd function
So now lets move to the first question
1)f(x)=cotx+4cosecx+x
ANSWER:- odd function,
f(-x)=-cotx-4cosecx-x => -(cotx+4cosecx+x)=> f(-x)=-f(x) ,so its an odd function.
2)similarly second you solve you will get even function.
f(x)=secx+4cosx+3x*2
for f(-x) you will get same function f(-x)=secx+4cosx+3x*2, so its an even funcion.
3)Now when you come to third you will get this is nor a odd niether even function. WHY? lets check
f(x)=sinx+cosx =>f(-x)= -sinx+cosx which is neither as equal to -f(x) nor as f(x)
so you can call it neither odd nor even
HOPE IT HELPED:)
THANKS
Answered by
0
Answer:
⊕²³√∛·×÷±≈≤≠∞∨∧∉∈⇔,⇒≅≡≥αβΔπФω↑↓∵∴↔⊆⊃⊂∑∫⇆⇄⇅⇵←→⊇⊄⊅∀°∠∡⊥∪∩∅¬⊕║∦∝∞㏒㏑
Step-by-step explanation:
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