Question

d. Find the greatest number that divides 231 and 156 leaving a remainder of 6 in each case
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Answer 1

SOLUTION

TO DETERMINE

The greatest number that divides 231 and 156 leaving a remainder of 6 in each case

TO DETERMINE

Here the required number is the greatest number that divides 231 and 156 leaving a remainder of 6 in each case

Hence the required number is the greatest number that divides 231 - 6 and 156 - 6 completely

In other words the required number is the largest number which divides 225 , 150 completely

We have to find the HCF of 225 , 150

Here the given numbers are 225 , 150

225 = 3 × 3 × 5 × 5

150 = 2 × 3 × 5 × 5

HCF

= 3 × 3 × 5

= 75

FINAL ANSWER

The greatest number that divides 231 and 156 leaving a remainder of 6 in each case is 75

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