Question

d) Find the perimeter of the rectangle whose length = 31cm and breadth
=10cm​

Answer 1

$\sf \large \underbrace{ \underline{Understanding \: the \: Concept}}$

Here's the concept of perimeter of rectangle is used. The length and breadth of rectangle are given to be 32cm and 10cm and we have to find the perimeter of rectangle which we could easily find by applying formula of perimeter of rectangle.

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So let's start!

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GIVEN:

⊙ Length of rectangle=31cm

⊙ Breadth of rectangle=10cm

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TO FIND:

⊙ Perimeter of rectangle

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SOLUTION:

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$\sf&#10029Perimeter \: of \: rectangle=2(L+B)$

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$\small \sf[Here \: L \: and \: B \: refers \: to \: Length \: and \: breadth \: respectively]$

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$\sf : \implies \: \: 2(31 + 10)m$

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$\sf : \implies \: \: 2(41m)$

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$\color{orange} \large \boxed{ \sf : \implies \: \: 82m}$

Hence the perimeter of rectangle is 82m.

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$\sf \large \underbrace{ \underline{More \: formulae \: to \: know}}$

$\sf⊙ \: Area \: of \: rectangle=Length×Breadth$

$\sf ⊙ \: Area \: of \: square=Side²$

$\sf \: ⊙ \: Area \: of \: circle=πr²$

$\sf \:⊙ \: Area \: of \: triangle=\dfrac{1}{2}×Base×Height ‎ ‎$

$\sf \: ⊙ \: Perimeter \: of \: square=4×Side$

$\sf \: ⊙ \: Perimeter \: of \: circle=2πr$

Answer 2

HELLO, AKASH KUMAR GIRI

I AM SENDING YOU SOLUTION OF YOUR QUESTION.

ONLY REMEMBER FOR SOLVING PERIMETER AND AREA QUESTIONS YOU SHOULD LEARN THE FORMULAS. AND IF YOU THINK YOU HAD BENEFIT FROM MY ANSWER PLS MARK MY ANSWER BRAINLIEST.

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