Question

(d) Find the perpendicular bisector point of the line
segment joining the points A (-2, -5) and B (2,5). [1]​

Answer 1

A(-2,-5)(x1,y1),B(2,5)(X2,y2)

-2+2/2,-5+5/2=0,0

slope of AB=5-5/2-2=0

slope of line perp to AB=0/slope of AB

for perp bisector m=0,(x1y1)=(0,0)

Step-by-step explanation:

let the midpoint be p using formula[x1+X2/2,y1+y2/2]

the we should find the slope using formula y2-y1/x2-x1

the next we have to find slope of line perpendicular to AB using formula=-1/slope of AB

then find for perpendicular bisector

#answerwithquality

#bal