Math, asked by parmgill878, 7 months ago

(d) Find the radius of curvature at origin of the curve
x - 3x²y + 4xy2 - 4y +6x² - 8xy +9y-6y=0​

Answers

Answered by Yengalthilak12
3

x - 3 {x}^{2} y + 4xy {}^{2}  - 4y + 6 {x}^{2}  - 8xy + 9y - 6y = 0

3xy + 4xy {}^{2}   - 10 {x}^{2} y - 8xy + 3 = 0

7 {x}^{2}  {y}^{3}  - 2x + 3 = 0

9xy {}^{3}  + 3 = 0

11x {y}^{3}  = 0

xy {}^{3}  = 0 - 11

xy {}^{3}  =  - 11

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