Question

D first question:the density of mercury is 1.36*10^4kgm^-3 at 0C And at 22C take cubic expansivity of mercury as equal to 180*10^-6 k-1

Answer 1

Answer:

ρ = 1.355 × 10⁴

Explanation:

The change in density due to thermal expansion is given by

Δρ = ρ₀ × Ɣ × ΔT

∴ ρ = ρ₀ - Δρ

⇒ ρ = ρ₀(1 - ƔΔT)

⇒ ρ = 1.36 × 10⁴ ( 1 - {180 × 10⁻⁶ × 22})

⇒ ρ = 1.355 × 10⁴