Question

(d) How much of CO2 and H2O are produced when 90 g of glucose is decomposed ?​

Answer 1

Answer:

Approximately  

60g of C6H12O6

Explanation:

We have the balanced equation (without state symbols): 6H2O + 6CO2

→ C6H12O6 + 6O2

So, we would need six moles of carbon dioxide to fully produce one mole of glucose.

Here, we got  

88 g of carbon dioxide, and we need to convert it into moles.

Carbon dioxide has a molar mass of 44 g/mol

So here, there exist 88 g 44 g/mol

= 2 mol

Since there are two moles of  CO2

, we can produce 261 = 13 moles of glucose  (C6H12O6)

We need to find the mass of the glucose produced, so we multiply the number of moles of glucose by its molar mass.

Glucose has a molar mass of  

180.156

 

g/mol

. So here, the mass of glucose produced is

1

3

mol

⋅

180.156

 

g

mol

≈

60

 

g

to the nearest whole number.

So, approximately  

60

grams of glucose will be produced