Physics, asked by Anonymous, 17 hours ago

d) If a 90 W electric bulb is lighted for 3 hours how much electrical energy is consumed?​

Answers

Answered by nimeshbhaskar2005
0

Explanation:

Energy = Power*time

Energy consumed by 100 W bulb per day = 2∗100 Wh

= 0.2 kWh

Energy consumed by 40 W bulbs per day = 4∗40∗4 Wh

= 0.64 kWh

Total energy consumed per day = 0.2 + 0.64 kWh

= 0.84 kWh

Therefore, the energy consumed in 30 days = 30∗0.84 kWh

= 25.2 kWh

Answered by bitaniamak
0

Explanation:

Hi..........

here is neat and precise answer for that as we all know energy = power x time therefore

E=90w x 3hr = 270kwh

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