d) In the given figure, XY || PZ, then the measure of (q + r) is
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In △PXY and △PQR,XY is parallel to QR, so corresponding angles are equal.
∠PXY=∠PQR
∠PYX=∠PRQ
Hence, △PXY∼△PQR [By AA similarity criterion]
PQ
PX
=
QR
XY
⇒
1+3
1
=
QR
XY
⇒
4
1
=
9
XY
⇒XY=2.25 cm
We know that the ratio of areas of two similar triangles is equal to the ratio of the squares of their corresponding sides.
ar(△PQR)
ar(△PXY)
=(
PQ
PX
)
2
⇒
ar(△PQR)
A
=
16
1
⇒ar(△PQR)=16A cm
2
Now, ar(trapeziumXYRQ)=(16A−A)cm
2
=15A cm
2
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