Question

D is a point on base BC of a ∆ABC such that
2BD = DC. Prove that : ar(∆ABD) = 1/3 ar∆ABC).​

Answer 1

Answer:

Since a point on the line dc the mid point of dc such that bd eques de equels ec.

Therefore base is equal and hight is command. So are of the tringle abd = area of the tringle ade=aec. So area of the tringle abd =1/3rd abc.