D is a point on BC in triangle ABC such that AB=AD.Show that BC is greater than AB
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Step-by-step explanation:
AD=AC
Angles opposite to equal sides are equal
So, ACD=ADC
Now, ∠ADC is an exterior angle of △ABD
ADC=ABD+∠BAD since exterior angle is sum of interior opposite angles.
So, Angle ADC>Angle Abd
ACD>ABD since side opposite to the greater angle is longer
AB>AD as AC=AD given
Hence proved.
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