Math, asked by saradagogoi82, 13 days ago

D is a point on BC in triangle ABC such that AB=AD.Show that BC is greater than AB​

Answers

Answered by sarvan52
0

Step-by-step explanation:

AD=AC

Angles opposite to equal sides are equal

So, ACD=ADC

Now, ∠ADC is an exterior angle of △ABD

ADC=ABD+∠BAD since exterior angle is sum of interior opposite angles.

So, Angle ADC>Angle Abd

ACD>ABD since side opposite to the greater angle is longer

AB>AD as AC=AD given

Hence proved.

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