Question

D is a point on BC of triangle
ABC such that AD=AC. Show that AB>AD.​

Answer 1

Step-by-step explanation:

Given = AD = AC

Angle Of Opposite to equal Side are equal

So , angle ACD = angle ADC ..... 1

Now angle ADC is an exterior angle of ∆ ABD

angle ADC = angle ABD + angle BAD Since exterior

Angle is Sum of Interior Opposite angle

So , angle ADC Greater than angle ABD

= angle ADC Greater than angle ABD Since Side Opposite to the greater angel is longer

Some Information

Exterior Angle Theorem

Exterior Angle Is equal To Sum Of Two Interior Opposite angle

Answer 2

Answer:

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