Math, asked by zak99, 11 months ago

D is a point on side BC of AABC such that
AD = AC. Show that AB > AC.

Answers

Answered by gungunjain32

3

Answer:

GIVEN: D is a point on the side BC of triangle ABC such that BD/CD = AB/AC. TO PROVE: AD bisects <BAC (that is, <BAD = <DAC).

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