D is a point on side BC of ΔABC such that AD = AC. Prove that AB ˃ AC
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AD=AC
So angle ACD=angle ADC
Now angle ADC =angle ABD +angle BAD
So angle angle ADC > angle ABD
angle ACD > angle ABD
AB>AC
So angle ACD=angle ADC
Now angle ADC =angle ABD +angle BAD
So angle angle ADC > angle ABD
angle ACD > angle ABD
AB>AC
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