Question

D is a point on side BC of ∆ ABC such that AD = AC (see figure ok) and show that AB > AD.​

Answer 1

Answer:

D is a point on side BC of ∆ ABC such that AD = AC.

In ∆ DAC,

AD = AC (Given)

So, ∠ ADC = ∠ ACD (Angles opposite to equal sides)

Now:-

∠ ADC is an exterior angle for ∆ABD.

So, ∠ ADC > ∠ ABD

or, ∠ ACD > ∠ ABD

or, ∠ ACD > ∠ ABC

or, ∠ ACB > ∠ ABC

So, AB > AC (Side opposite to larger angle in ∆ABC)

or, AB > AD (AD = AC)

Thus, proved.