D is a point on side bc of ABC such that bd/cd=ab/ac. Prove that ad is the bisector of angle bac
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Answer:
given : BD/CD = AB/AC → AC/CD = AB/AD
in Δles ABD & ACD
AB/AD = AC/CD
AD = AD
∴ΔABD is similar to ΔACD (SSS)
→ ∠DAB = ∠DAC
∴ AD is the bisector of angle ∠BAC
hope its useful..................
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