D is a point on the base BC of an isosceles triangle
ABC in which AB = AC. The triangle ADE is drawn
such that AD = AE, ZDAE = ZBAC and D, E are
on opposite sides of AC. Prove that
(1) ZBAD = ZCAE
(ii) triangles BAD and CAE are congruent
(iii) AC bisects ZBCE.
Answers
Answered by
3
Step-by-step explanation:
Since ΔADE∼ΔABC,
∴
AB
AD
=
BC
DE
=
AC
AE
⇒
AE
DE
=
AE
DE
=
3
2
⇒DE:AE=2:3
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