Question

D is a point on the circumcircle of ∆ABC in which AB=AC such that B and D are on the opposite side of line AC. If CD is produced to a point E such that CE=BD, prove that AD=AE.​

Answer 1

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$\huge\bold\purple{Answer:-}$

⏩ We have,

AB=AC and CE=BD

In ∆'s ABD and ACE, we have

→ AB=AC (Given)

→angle ABD= angle ACE (angles in the same segment)

→BD= CE (Given)

So, by SAS congruence criterion, we obtain

∆ ABD is congruent to ∆ ACE

=> AD= AE (CPCT)

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Answer 2

Step-by-step explanation:

hope it helps u.....❣️