D is a point on the circumference of a circum circle of ABC in AB = AC such that B and D are on opposite sides of AC. If CD is produced to point E such that CE = BD, prove that AD=AE
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⏩ We have,
AB=AC and CE=BD
In ∆'s ABD and ACE, we have
→ AB=AC (Given)
→angle ABD= angle ACE (angles in the same segment)
→BD= CE (Given)
So, by SAS congruence criterion, we obtain
∆ ABD is congruent to ∆ ACE
=> AD= AE (CPCT)
✔✔✔✔✔✔✔✔
Hope it helps...:-)
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